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12x^2+57x+45=0
a = 12; b = 57; c = +45;
Δ = b2-4ac
Δ = 572-4·12·45
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-33}{2*12}=\frac{-90}{24} =-3+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+33}{2*12}=\frac{-24}{24} =-1 $
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